Solution March 30, 2007

Problem

Let f(x,y) = 1 + x^{2}\,y^{4}+x^{4}\,y^{2}-3\,x^{2}\,y^{2}.

Determine whether there exist polynomials gi(x,y) with real coefficients such that

f = \sum_{i=1}^{k}g_{i}^{2}\qquad\qquad(1)

or argue that such a representation is not possible.

Solution

We will have to resort to arguing. Assume without loss of generality that g_i\neq 0. Let g_i\, be fully expanded to sums of terms of the form k x^ay^b\, with k\neq0.

Note that f(\pm1,\pm1) = 0, so

g_i(\pm1, \pm1) = 0,\qquad\qquad(2)

because a sum of squares of real numbers is zero if and only if all the numbers are zero.

If k=0\, we'd have f=0\,. So k>0\,.

Let d\, be the maximum degree of the g_i\,. Pick the smallest n\, such that there is a term k x^ny^{d-n}\, in one of the g_i\,. Then, by comparing coefficients in (1), we find that f\, contains a term of the form tx^{2n}y^{2d-2n}\, with t>0\, (t\, is the sum of at least one non-zero square, and thus positive), so f\, has degree at least 2d\,.

Therefore, the degree of g_i\, is at most 3.

By a similar argument, g_i(0,y)\, and g_i(x,0)\, must be constant, because f(0,y)\, and f(x,0)\, are constant polynomials.

This means that g_i(x,y) = a_ix^2y + b_ixy^2 + c_ixy + d_i\, (what we just said about g_i(x,0)\, and g_i(0,y)\, means that the coefficients for x,\,x^2,\,x^3,\,y,\,y^2 and y^3\, are zero) for some real numbers a_i,\,b_i,\,c_i,\,d_i. (2) is then equivalent to the following system of linear equations:

0 = + a_i + b_i + c_i + d_i\,
0 = + a_i - b_i - c_i + d_i\,
0 = - a_i + b_i - c_i + d_i\,
0 = - a_i - b_i + c_i + d_i\,

Solving these we find g_i = 0\,, contradicting our assumptions.